16=1/3(4-x)^2,

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Solution for 16=1/3(4-x)^2, equation: 



16=1/3(4-x)^2.

We move all terms to the left:

16-(1/3(4-x)^2.)=0



Domain of the equation: 3(4-x)^2.)!=0

x∈R



We add all the numbers together, and all the variables

-(1/3(-1x+4)^2.)+16=0

We multiply all the terms by the denominator


-(1+16*3(-1x+4)^2.)=0



We calculate terms in parentheses: -(1+16*3(-1x+4)^2.), so:

1+16*3(-1x+4)^2.

determiningTheFunctionDomain
16*3(-1x+4)^2.+1

Wy multiply elements

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We use the square of the difference formula

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